我在Spring Data Jpa中遇到了一个@EntityGraph的问题，它不能像我预期的那样运行。

@Entity
@Getter
@NoArgsConstructor(access = AccessLevel.PROTECTED)
@EntityListeners(AuditingEntityListener.class)
public class Board extends BaseTimeEntity {
    @Id @GeneratedValue
    private Long id;

    @JoinColumn(name = "writer_id")
    @ManyToOne(fetch = FetchType.LAZY)
    private User user;

    // others
}

@Entity
@Getter
@NoArgsConstructor(access = AccessLevel.PROTECTED)
@EntityListeners(AuditingEntityListener.class)
public class User extends BaseTimeEntity {
    @Id @GeneratedValue
    private Long id;

    // others 
}

字符串
这些是简化的实体及其关系。问题在于以下存储库方法：

@Repository
public interface BoardJpaRepository extends JpaRepository<Board, Long> {
    @EntityGraph(attributePaths = {"user"})
    Optional<Board> findById(Long id);
}

型
我打算在findById方法中使用@ bottyGraph来获取Board和User，但执行的查询只获取Board：

select
    b1_0.id,
    b1_0.content,
    b1_0.create_date,
    b1_0.modified_date,
    b1_0.title,
    b1_0.writer_id,
    b1_0.views 
from
    board b1_0 
where
    b1_0.id in (?,?,?)

型
此外，当我在BoardRepository中的其他查询方法中使用@ martyGraph时，它按预期工作：

@EntityGraph(attributePaths = {"user"})
Page<Board> findAll(Pageable pageable);

@EntityGraph(attributePaths = {"user"})
@Query("select b from Board b where b.user.username like %:username%")
Page<Board> findAllByUsernameLike(@Param(value = "username") String username, Pageable pageable);

@EntityGraph(attributePaths = {"user"})
@Query("select b from Board b where b.title like %:title%")
Page<Board> findAllByTitleLike(@Param(value = "title") String title, Pageable pageable);

@EntityGraph(attributePaths = {"user"})
@Query("select b from Board b where b.content like %:content%")
Page<Board> findAllByContentLike(@Param(value = "content")

select
        b1_0.id,
        b1_0.content,
        b1_0.create_date,
        b1_0.modified_date,
        b1_0.title,
        u1_0.id,
        u1_0.create_date,
        u1_0.email,
        u1_0.is_account_non_expired,
        u1_0.is_account_non_locked,
        u1_0.is_credentials_non_expired,
        u1_0.is_enabled,
        u1_0.modified_date,
        u1_0.name,
        u1_0.password,
        u1_0.username,
        b1_0.views 
    from
        board b1_0 
    join
        user u1_0 
            on u1_0.id=b1_0.writer_id 
    where
        u1_0.username like concat('%',?,'%') escape '' limit ?,?

我目前的版本是：

• Java 17
• Spring Boot 3.1.1
• Hibernate core 6.2.5.Final

然而，当我将Sping Boot 更新到3.2.0，将Hibernate Core更新到6.3.1.Final时，这个问题似乎得到了解决：

select
        b1_0.id,
        b1_0.content,
        b1_0.create_date,
        b1_0.modified_date,
        b1_0.title,
        u1_0.id,
        u1_0.create_date,
        u1_0.email,
        u1_0.is_account_non_expired,
        u1_0.is_account_non_locked,
        u1_0.is_credentials_non_expired,
        u1_0.is_enabled,
        u1_0.modified_date,
        u1_0.name,
        u1_0.password,
        u1_0.username,
        b1_0.views 
    from
        board b1_0 
    left join
        user u1_0 
            on u1_0.id=b1_0.writer_id 
    where
        b1_0.id=?

型
查询正确生成，并且由于Spring Batch而声明的in子句似乎也发生了变化。
我不太愿意简单地将其归因于版本问题，因为它感觉不像是一个已解决的问题。我很好奇这是否确实是一个与版本相关的问题，如果是，是否有任何相关的链接或文档？此外，我很想知道是否有针对原始版本的解决方案。