我是Haskell的新手。目前我正在做一个SQL项目，我在解析JSON文件内容时卡住了。我得到了一些该死的错误，我不知道如何修复它。
这是我的JSON文件：

{
"Table":"flags",
"Columns":[
  {"Name":"flag", "ColumnType":"StringType"},
  {"Name":"value", "ColumnType":"BoolType"}],
"Rows":[
  [{"Value":"StringValue a"}, {"Value":"BoolValue True"}],
  [{"Value":"StringValue b"}, {"Value":"BoolValue True"}],
  [{"Value":"StringValue b"}, {"Value":"NullValue"}],
  [{"Value":"StringValue b"}, {"Value":"BoolValue False"}]
  ]
}

字符串
这是我的Haskell代码：

data FromJSONColumn = FromJSONColumn {
  deserializedName :: String,
  deserializedDataType :: String
  } deriving (Show, Eq, Generic)

instance FromJSON FromJSONColumn where

parseJSON (Object v) =
  FromJSONColumn <$> v .: "Name"
  <*> v .: "ColumnType"

parseJSON _ = mzero

型
这是我得到的错误：

JSONExample.hs:17:27-32: error:
    • Couldn't match type ‘[Char]’ with ‘Key’
      Expected: Key
        Actual: String
    • In the second argument of ‘(.:)’, namely ‘"Name"’
      In the second argument of ‘(<$>)’, namely ‘v .: "Name"’
      In the first argument of ‘(<*>)’, namely
        ‘FromJSONColumn <$> v .: "Name"’
   |
17 |   FromJSONColumn <$> v .: "Name"
   |                           ^^^^^^

JSONExample.hs:18:12-23: error:
    • Couldn't match type ‘[Char]’ with ‘Key’
      Expected: Key
        Actual: String
    • In the second argument of ‘(.:)’, namely ‘"ColumnType"’
      In the second argument of ‘(<*>)’, namely ‘v .: "ColumnType"’
      In the expression:
        FromJSONColumn <$> v .: "Name" <*> v .: "ColumnType"
   |
18 |   <*> v .: "ColumnType"
   |            ^^^^^^^^^^^^

型
谁能解释一下如何为这样的文件（包含表的文件）写示例？我该怎么做？我真的迷路了。
P.S.这是我正在使用的数据类型：

data ColumnType
  = IntegerType
  | StringType
  | BoolType
  deriving (Show, Eq)

data Column = Column String ColumnType
  deriving (Show, Eq)

data Value
  = IntegerValue Integer
  | StringValue String
  | BoolValue Bool
  | NullValue
  deriving (Show, Eq)

type Row = [Value]

data DataFrame = DataFrame [Column] [Row]
  deriving (Show, Eq)

型