我是这样做的：

var cert2 = new X509Certificate2(cert);
string hostName = cert2.GetNameInfo(X509NameType.DnsName, false);

字符串
您还可以检查证书是否有效：

bool valid = cert2.Verify();

型
(See this question用于描述X509Certificate2类）

对于我的证书字符串，通过像这样的小调整，它工作得更好

public static List<string> Parse(string data, string delimiter)
{
    if (data == null) return null;
    if (!delimiter.EndsWith("=")) delimiter = delimiter + "=";
    if (!data.Contains(delimiter)) return null;
    //base case
    var result = new List<string>();
    int start = data.IndexOf(delimiter) + delimiter.Length;
    int length = data.IndexOf(',', start) - start;
    if (length == 0) return null; //the group is empty
    if (length > 0)
    {
        result.Add(data.Substring(start, length));
        //only need to recurse when the comma was found, because there could be more groups
        var rec = Parse(data.Substring(start + length), delimiter);
        if (rec != null) result.AddRange(rec); //can't pass null into AddRange() :(
    }
    else //no comma found after current group so just use the whole remaining string
    {
        result.Add(data.Substring(start));
    }
    return result;
}

字符串
...

var name = Parse(_cert.Subject, "CN").FirstOrDefault();
var email = Parse(_cert.Subject, "E").FirstOrDefault();

型

使用GetRawCertData方法获取证书的DER数据。然后创建X509 Certificate 2对象的示例，并使用Import（）方法加载原始证书数据。然后使用SubjectName属性访问各个主题字段。注意-您还需要检查主题替代名称扩展，但不幸的是，在.NET Framework类中没有简单的方法来做到这一点（您可能会发现有必要使用第三方PKI库进行适当的证书验证和管理）。

我使用以下方法解析AD返回的字符串，它可能有助于解析您接收的数据：

/// <summary>
/// Recursively searches the supplied AD string for all groups.
/// </summary>
/// <param name="data">The string returned from AD to parse for a group.</param>
/// <param name="delimiter">The string to use as the seperator for the data. ex. ","</param>
/// <returns>null if no groups were found -OR- data is null or empty.</returns>
public static List<string> Parse(string data, string delimiter)
{
    if (data == null) return null;

    if (!delimiter.EndsWith("=")) delimiter = delimiter + "=";

    //data = data.ToUpper(); // why did i add this?
    if (!data.Contains(delimiter)) return null;

    //base case
    var result = new List<string>();
    int start = data.IndexOf(delimiter) + 3;
    int length = data.IndexOf(',', start) - start;
    if (length == 0) return null; //the group is empty
    if (length > 0)
    {
        result.Add(data.Substring(start, length));

        //only need to recurse when the comma was found, because there could be more groups
        var rec = Parse(data.Substring(start + length), delimiter);
        if (rec != null) result.AddRange(rec); //can't pass null into AddRange() :(
    }
    else //no comma found after current group so just use the whole remaining string
    {
        result.Add(data.Substring(start));            
    }

    return result;
}

字符串
因此，给予一个字符串，如“CN=my common name，CN=another common name，O=my orginization”，它将返回一个包含两个公共名称的列表。