给定

a searchString "*** test text before string *** john doe | test string after string"

和

一个MongoDB文档：

{
  "name": "John Doe",
  "matchingWords": [
    "john doe", "another string"
  ]
}

字符串

I WANT TO查询任何在searchString中找到的matchingWords字段（string[]）中至少有一个元素的文档。！！matchingWords中的元素可能包含空格。
预期结果：找到上面的mongoDB文档，因为在searchString中找到了元素“john doe”。
问题

下面的代码只在matchingWords元素不包含空格时才有效.

private async findByMatchingWords(searchString: string): Promise<boolean> {
if (!searchString) return false;

const lowerCaseSearchStrings: string[] = searchString.toLowerCase().split(' ');
const results = await paymentPartyModel
  .find<IPaymentParty>({
    matchingWords: {
      $exists: true,
      $not: { $size: 0 }, // Check if array exists and is not empty
      $in: lowerCaseSearchStrings,
    },
  })
  .lean();

if (!results || results.length === 0) {
  return false;
} else if (results.length === 1) {
  this.info = results[0];
  return true;
} else {
  // 2 or more matches found...
  Todo('What to do when more than one payment party matches the search?');
  return false;
}

型
}