我看了其他问题：）
如Is there a faster/shorter way to initialize variables in a Rust struct?
我也在其他帮助答案和文档中看到了这一点。但是下面与提供的模式匹配的代码无法编译。|我该怎么办？

#[derive(Default)]
pub struct Foo2 {
    pub name: String,
    pub test_int: i32,
}

impl Default for Foo2 {
    fn default() -> Self {
        Foo2 {
            name: "Default Name".to_string(),
            test_int: 999,
        }
    }
}

impl Foo2 {
    pub fn print2(&self) {
        println!("Print name: \"{}\" int: {}", self.name, self.test_int );
    }
}

fn foo2_test() {

    let f2 = Foo2 {
        test_int: 1234,
        ..Foo2::Default::default()
    };
    f2.print2();
}

字符串
我得到这个错误：（我使用的是稳定版本）

error[E0119]: conflicting implementations of trait `std::default::Default` for type `Foo2`
   --> src/init_test.rs:99:10
    |
99  | #[derive(Default)]
    |          ^^^^^^^ conflicting implementation for `Foo2`
...
106 | impl Default for Foo2 {
    | --------------------- first implementation here
    |
    = note: this error originates in the derive macro `Default` (in Nightly builds, run with -Z macro-backtrace for more info)

型
当我注解掉：

#[derive(Default)]

型
我得到另一个错误：

error[E0223]: ambiguous associated type
   --> src/init_test.rs:125:11
    |
125 |         ..Foo2::Default::default()
    |           ^^^^^^^^^^^^^
    |
help: if there were a trait named `Example` with associated type `Default` implemented for `Foo2`, you could use the fully-qualified path
    |
125 |         ..<Foo2 as Example>::Default::default()
    |           ~~~~~~~~~~~~~~~~~~~~~~~~~~

型