android.widget.CheckBox.getVisibility()方法的使用及代码示例

x33g5p2x  于2022-01-18 转载在 其他  
字(1.1k)|赞(0)|评价(0)|浏览(162)

本文整理了Java中android.widget.CheckBox.getVisibility()方法的一些代码示例,展示了CheckBox.getVisibility()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。CheckBox.getVisibility()方法的具体详情如下:
包路径:android.widget.CheckBox
类名称:CheckBox
方法名:getVisibility

CheckBox.getVisibility介绍

暂无

代码示例

代码示例来源:origin: seven332/EhViewer

@Override
  public void onClick(View v) {
    if (v == mCancel) {
      finish();
    } else if (v == mSet) {
      if (null != mPatternView && null != mFingerprint) {
        String security;
        if (mPatternView.getCellSize() <= 1) {
          security = "";
        } else {
          security = mPatternView.getPatternString();
        }
        Settings.putSecurity(security);
        Settings.putEnableFingerprint(mFingerprint.getVisibility() == View.VISIBLE &&
            mFingerprint.isChecked() && !security.isEmpty());
      }
      finish();
    }
  }
}

代码示例来源:origin: stackoverflow.com

ListView menuList = (ListView) findViewById(R.id.listview_Menu);
   for(int i=0; i < menuList.getChildCount(); i++){
     LinearLayout itemLayout = (LinearLayout)menuList.getChildAt(i);
     CheckBox cb = (CheckBox)itemLayout.findViewById(R.id.listview_checkbox_item);
     cb.setVisibility((cb.getVisibility() == View.VISIBLE)? View.INVISIBLE :  View.VISIBLE);
   }

相关文章