本文整理了Java中android.graphics.Matrix.mapVectors()方法的一些代码示例，展示了Matrix.mapVectors()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台，是从一些精选项目中提取出来的代码，具有较强的参考意义，能在一定程度帮忙到你。Matrix.mapVectors()方法的具体详情如下：
包路径：android.graphics.Matrix
类名称：Matrix
方法名：mapVectors

Matrix.mapVectors介绍

暂无

代码示例

代码示例来源：origin: robolectric/robolectric

@Test
public void testMapVectors() {
 final Matrix matrix = new Matrix();
 matrix.postTranslate(-1.0f, -2.0f);
 matrix.postScale(2.0f, 3.0f);
 final float[] input = {
   0.0f, 0.0f,
   1.0f, 2.0f
 };
 final float[] output = new float[input.length];
 matrix.mapVectors(output, input);
 assertThat(output)
   .usingExactEquality()
   .containsExactly(0.0f, 0.0f, 2.0f, 6.0f);
}

代码示例来源：origin: burhanrashid52/PhotoEditor

private static void adjustTranslation(View view, float deltaX, float deltaY) {
  float[] deltaVector = {deltaX, deltaY};
  view.getMatrix().mapVectors(deltaVector);
  view.setTranslationX(view.getTranslationX() + deltaVector[0]);
  view.setTranslationY(view.getTranslationY() + deltaVector[1]);
}

代码示例来源：origin: GcsSloop/ViewSupport

private static float transformAngle(Matrix m, float angleRadians) {
    // Construct and transform a vector oriented at the specified clockwise
    // angle from vertical.  Coordinate system: down is increasing Y, right is
    // increasing X.
    float[] v = new float[2];
    v[0] = (float) Math.sin(angleRadians);
    v[1] = (float) Math.cos(angleRadians);
    m.mapVectors(v);
    // Derive the transformed vector's clockwise angle from vertical.
    float result = (float) Math.atan2(v[0], -v[1]);
    if (result < -Math.PI / 2) {
      result += Math.PI;
    } else if (result > Math.PI / 2) {
      result -= Math.PI;
    }
    return result;
  }
}

代码示例来源：origin: alexjlockwood/kyrie

final float getMatrixScale(Matrix matrix) {
 // Given unit vectors A = (0, 1) and B = (1, 0).
 // After matrix mapping, we got A' and B'. Let theta = the angle b/t A' and B'.
 // Therefore, the final scale we want is min(|A'| * sin(theta), |B'| * sin(theta)),
 // which is (|A'| * |B'| * sin(theta)) / max (|A'|, |B'|);
 // If max (|A'|, |B'|) = 0, that means either x or y has a scale of 0.
 // For non-skew case, which is most of the cases, matrix scale is computing exactly the
 // scale on x and y axis, and take the minimal of these two.
 // For skew case, an unit square will mapped to a parallelogram. And this function will
 // return the minimal height of the 2 bases.
 final float[] unitVectors = tempUnitVectors;
 unitVectors[0] = 0;
 unitVectors[1] = 1;
 unitVectors[2] = 1;
 unitVectors[3] = 0;
 matrix.mapVectors(unitVectors);
 final float scaleX = (float) Math.hypot(unitVectors[0], unitVectors[1]);
 final float scaleY = (float) Math.hypot(unitVectors[2], unitVectors[3]);
 final float crossProduct =
   cross(unitVectors[0], unitVectors[1], unitVectors[2], unitVectors[3]);
 final float maxScale = Math.max(scaleX, scaleY);
 return maxScale > 0 ? Math.abs(crossProduct) / maxScale : 0;
}

代码示例来源：origin: eventtus/photo-editor-android

private static void adjustTranslation(View view, float deltaX, float deltaY) {
  float[] deltaVector = {deltaX, deltaY};
  view.getMatrix().mapVectors(deltaVector);
  view.setTranslationX(view.getTranslationX() + deltaVector[0]);
  view.setTranslationY(view.getTranslationY() + deltaVector[1]);
}

代码示例来源：origin: PeterStaev/nativescript-photo-editor

private static void adjustTranslation(View view, float deltaX, float deltaY) {
  float[] deltaVector = {deltaX, deltaY};
  view.getMatrix().mapVectors(deltaVector);
  view.setTranslationX(view.getTranslationX() + deltaVector[0]);
  view.setTranslationY(view.getTranslationY() + deltaVector[1]);
}