本文整理了Java中java.security.Provider.setProviderNumber()
方法的一些代码示例,展示了Provider.setProviderNumber()
的具体用法。这些代码示例主要来源于Github
/Stackoverflow
/Maven
等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。Provider.setProviderNumber()
方法的具体详情如下:
包路径:java.security.Provider
类名称:Provider
方法名:setProviderNumber
[英]Set the provider preference order number.
[中]设置提供商首选项订单号。
代码示例来源:origin: robovm/robovm
/**
*
* Update sequence numbers of all providers.
*
*/
private static void renumProviders() {
Provider[] p = Services.getProviders();
for (int i = 0; i < p.length; i++) {
p[i].setProviderNumber(i + 1);
}
}
代码示例来源:origin: robovm/robovm
/**
* Removes the {@code Provider} with the specified name form the collection
* of providers. If the the {@code Provider} with the specified name is
* removed, all provider at a greater position are shifted down one
* position.
*
* <p>Returns silently if {@code name} is {@code null} or no provider with the
* specified name is installed.
*
* @param name
* the name of the provider to remove.
*/
public static synchronized void removeProvider(String name) {
// It is not clear from spec.:
// 1. if name is null, should we checkSecurityAccess or not?
// throw SecurityException or not?
// 2. as 1 but provider is not installed
// 3. behavior if name is empty string?
Provider p;
if ((name == null) || (name.length() == 0)) {
return;
}
p = getProvider(name);
if (p == null) {
return;
}
Services.removeProvider(p.getProviderNumber());
renumProviders();
p.setProviderNumber(-1);
}
代码示例来源:origin: MobiVM/robovm
/**
*
* Update sequence numbers of all providers.
*
*/
private static void renumProviders() {
Provider[] p = Services.getProviders();
for (int i = 0; i < p.length; i++) {
p[i].setProviderNumber(i + 1);
}
}
代码示例来源:origin: ibinti/bugvm
/**
*
* Update sequence numbers of all providers.
*
*/
private static void renumProviders() {
Provider[] p = Services.getProviders();
for (int i = 0; i < p.length; i++) {
p[i].setProviderNumber(i + 1);
}
}
代码示例来源:origin: com.gluonhq/robovm-rt
/**
*
* Update sequence numbers of all providers.
*
*/
private static void renumProviders() {
Provider[] p = Services.getProviders();
for (int i = 0; i < p.length; i++) {
p[i].setProviderNumber(i + 1);
}
}
代码示例来源:origin: com.bugvm/bugvm-rt
/**
*
* Update sequence numbers of all providers.
*
*/
private static void renumProviders() {
Provider[] p = Services.getProviders();
for (int i = 0; i < p.length; i++) {
p[i].setProviderNumber(i + 1);
}
}
代码示例来源:origin: com.mobidevelop.robovm/robovm-rt
/**
*
* Update sequence numbers of all providers.
*
*/
private static void renumProviders() {
Provider[] p = Services.getProviders();
for (int i = 0; i < p.length; i++) {
p[i].setProviderNumber(i + 1);
}
}
代码示例来源:origin: FlexoVM/flexovm
/**
*
* Update sequence numbers of all providers.
*
*/
private static void renumProviders() {
Provider[] p = Services.getProviders();
for (int i = 0; i < p.length; i++) {
p[i].setProviderNumber(i + 1);
}
}
代码示例来源:origin: MobiVM/robovm
/**
* Removes the {@code Provider} with the specified name form the collection
* of providers. If the the {@code Provider} with the specified name is
* removed, all provider at a greater position are shifted down one
* position.
*
* <p>Returns silently if {@code name} is {@code null} or no provider with the
* specified name is installed.
*
* @param name
* the name of the provider to remove.
*/
public static synchronized void removeProvider(String name) {
// It is not clear from spec.:
// 1. if name is null, should we checkSecurityAccess or not?
// throw SecurityException or not?
// 2. as 1 but provider is not installed
// 3. behavior if name is empty string?
Provider p;
if ((name == null) || (name.length() == 0)) {
return;
}
p = getProvider(name);
if (p == null) {
return;
}
Services.removeProvider(p.getProviderNumber());
renumProviders();
p.setProviderNumber(-1);
}
代码示例来源:origin: ibinti/bugvm
/**
* Removes the {@code Provider} with the specified name form the collection
* of providers. If the the {@code Provider} with the specified name is
* removed, all provider at a greater position are shifted down one
* position.
*
* <p>Returns silently if {@code name} is {@code null} or no provider with the
* specified name is installed.
*
* @param name
* the name of the provider to remove.
*/
public static synchronized void removeProvider(String name) {
// It is not clear from spec.:
// 1. if name is null, should we checkSecurityAccess or not?
// throw SecurityException or not?
// 2. as 1 but provider is not installed
// 3. behavior if name is empty string?
Provider p;
if ((name == null) || (name.length() == 0)) {
return;
}
p = getProvider(name);
if (p == null) {
return;
}
Services.removeProvider(p.getProviderNumber());
renumProviders();
p.setProviderNumber(-1);
}
代码示例来源:origin: com.bugvm/bugvm-rt
/**
* Removes the {@code Provider} with the specified name form the collection
* of providers. If the the {@code Provider} with the specified name is
* removed, all provider at a greater position are shifted down one
* position.
*
* <p>Returns silently if {@code name} is {@code null} or no provider with the
* specified name is installed.
*
* @param name
* the name of the provider to remove.
*/
public static synchronized void removeProvider(String name) {
// It is not clear from spec.:
// 1. if name is null, should we checkSecurityAccess or not?
// throw SecurityException or not?
// 2. as 1 but provider is not installed
// 3. behavior if name is empty string?
Provider p;
if ((name == null) || (name.length() == 0)) {
return;
}
p = getProvider(name);
if (p == null) {
return;
}
Services.removeProvider(p.getProviderNumber());
renumProviders();
p.setProviderNumber(-1);
}
代码示例来源:origin: com.gluonhq/robovm-rt
/**
* Removes the {@code Provider} with the specified name form the collection
* of providers. If the the {@code Provider} with the specified name is
* removed, all provider at a greater position are shifted down one
* position.
*
* <p>Returns silently if {@code name} is {@code null} or no provider with the
* specified name is installed.
*
* @param name
* the name of the provider to remove.
*/
public static synchronized void removeProvider(String name) {
// It is not clear from spec.:
// 1. if name is null, should we checkSecurityAccess or not?
// throw SecurityException or not?
// 2. as 1 but provider is not installed
// 3. behavior if name is empty string?
Provider p;
if ((name == null) || (name.length() == 0)) {
return;
}
p = getProvider(name);
if (p == null) {
return;
}
Services.removeProvider(p.getProviderNumber());
renumProviders();
p.setProviderNumber(-1);
}
代码示例来源:origin: com.mobidevelop.robovm/robovm-rt
/**
* Removes the {@code Provider} with the specified name form the collection
* of providers. If the the {@code Provider} with the specified name is
* removed, all provider at a greater position are shifted down one
* position.
*
* <p>Returns silently if {@code name} is {@code null} or no provider with the
* specified name is installed.
*
* @param name
* the name of the provider to remove.
*/
public static synchronized void removeProvider(String name) {
// It is not clear from spec.:
// 1. if name is null, should we checkSecurityAccess or not?
// throw SecurityException or not?
// 2. as 1 but provider is not installed
// 3. behavior if name is empty string?
Provider p;
if ((name == null) || (name.length() == 0)) {
return;
}
p = getProvider(name);
if (p == null) {
return;
}
Services.removeProvider(p.getProviderNumber());
renumProviders();
p.setProviderNumber(-1);
}
代码示例来源:origin: FlexoVM/flexovm
/**
* Removes the {@code Provider} with the specified name form the collection
* of providers. If the the {@code Provider} with the specified name is
* removed, all provider at a greater position are shifted down one
* position.
*
* <p>Returns silently if {@code name} is {@code null} or no provider with the
* specified name is installed.
*
* @param name
* the name of the provider to remove.
*/
public static synchronized void removeProvider(String name) {
// It is not clear from spec.:
// 1. if name is null, should we checkSecurityAccess or not?
// throw SecurityException or not?
// 2. as 1 but provider is not installed
// 3. behavior if name is empty string?
Provider p;
if ((name == null) || (name.length() == 0)) {
return;
}
p = getProvider(name);
if (p == null) {
return;
}
Services.removeProvider(p.getProviderNumber());
renumProviders();
p.setProviderNumber(-1);
}
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