org.eclipse.jgit.lib.Repository.resolveSimple()方法的使用及代码示例

x33g5p2x  于2022-01-28 转载在 其他  
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本文整理了Java中org.eclipse.jgit.lib.Repository.resolveSimple方法的一些代码示例,展示了Repository.resolveSimple的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。Repository.resolveSimple方法的具体详情如下:
包路径:org.eclipse.jgit.lib.Repository
类名称:Repository
方法名:resolveSimple

Repository.resolveSimple介绍

暂无

代码示例

代码示例来源:origin: org.eclipse.jgit/org.eclipse.jgit

@Nullable
private RevObject parseSimple(RevWalk rw, String revstr) throws IOException {
  ObjectId id = resolveSimple(revstr);
  return id != null ? rw.parseAny(id) : null;
}

代码示例来源:origin: org.eclipse.jgit/org.eclipse.jgit

if (findRef(name) != null)
  return name;
return resolveSimple(name);

代码示例来源:origin: berlam/github-bucket

@Nullable
private RevObject parseSimple(RevWalk rw, String revstr) throws IOException {
  ObjectId id = resolveSimple(revstr);
  return id != null ? rw.parseAny(id) : null;
}

代码示例来源:origin: sonia.jgit/org.eclipse.jgit

@Nullable
private RevObject parseSimple(RevWalk rw, String revstr) throws IOException {
  ObjectId id = resolveSimple(revstr);
  return id != null ? rw.parseAny(id) : null;
}

代码示例来源:origin: sonia.jgit/org.eclipse.jgit

if (getRef(name) != null)
  return name;
return resolveSimple(name);

代码示例来源:origin: berlam/github-bucket

if (findRef(name) != null)
  return name;
return resolveSimple(name);

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Repository类方法