akka.stream.javadsl.Source.concat()方法的使用及代码示例

x33g5p2x  于2022-01-30 转载在 其他  
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本文整理了Java中akka.stream.javadsl.Source.concat()方法的一些代码示例,展示了Source.concat()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。Source.concat()方法的具体详情如下:
包路径:akka.stream.javadsl.Source
类名称:Source
方法名:concat

Source.concat介绍

暂无

代码示例

代码示例来源:origin: wxyyxc1992/Backend-Boilerplates

public static TextMessage handleTextMessage(TextMessage msg) {
  if (msg.isStrict()) // optimization that directly creates a simple response...
  {
    return TextMessage.create("Hello " + msg.getStrictText());
  } else // ... this would suffice to handle all text messages in a streaming fashion
  {
    return TextMessage.create(Source.single("Hello ").concat(msg.getStreamedText()));
  }
}
//#websocket-handler

代码示例来源:origin: org.eclipse.ditto/ditto-services-utils-akka

Source.fromIterator(typedElements::iterator)
    .flatMapConcat(this::mapEntity)
    .concat(Source.single(DOES_NOT_HAVE_NEXT_MSG))
    .mapAsync(1, msgToForward -> {
      if (DOES_NOT_HAVE_NEXT_MSG.equals(msgToForward)) {

代码示例来源:origin: eclipse/ditto

Source.fromIterator(typedElements::iterator)
    .flatMapConcat(this::mapEntity)
    .concat(Source.single(DOES_NOT_HAVE_NEXT_MSG))
    .mapAsync(1, msgToForward -> {
      if (DOES_NOT_HAVE_NEXT_MSG.equals(msgToForward)) {

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