okhttp3.internal.Util.inet6AddressToAscii()方法的使用及代码示例

x33g5p2x  于2022-02-01 转载在 其他  
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本文整理了Java中okhttp3.internal.Util.inet6AddressToAscii()方法的一些代码示例,展示了Util.inet6AddressToAscii()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。Util.inet6AddressToAscii()方法的具体详情如下:
包路径:okhttp3.internal.Util
类名称:Util
方法名:inet6AddressToAscii

Util.inet6AddressToAscii介绍

[英]Encodes an IPv6 address in canonical form according to RFC 5952.
[中]

代码示例

代码示例来源:origin: square/okhttp

if (inetAddress == null) return null;
byte[] address = inetAddress.getAddress();
if (address.length == 16) return inet6AddressToAscii(address);
if (address.length == 4) return inetAddress.getHostAddress(); // An IPv4-mapped IPv6 address.
throw new AssertionError("Invalid IPv6 address: '" + host + "'");

代码示例来源:origin: com.squareup.okhttp3/okhttp

if (inetAddress == null) return null;
byte[] address = inetAddress.getAddress();
if (address.length == 16) return inet6AddressToAscii(address);
if (address.length == 4) return inetAddress.getHostAddress(); // An IPv4-mapped IPv6 address.
throw new AssertionError("Invalid IPv6 address: '" + host + "'");

代码示例来源:origin: apache/servicemix-bundles

if (inetAddress == null) return null;
byte[] address = inetAddress.getAddress();
if (address.length == 16) return inet6AddressToAscii(address);
throw new AssertionError("Invalid IPv6 address: '" + host + "'");

代码示例来源:origin: com.github.ljun20160606/okhttp

if (inetAddress == null) return null;
byte[] address = inetAddress.getAddress();
if (address.length == 16) return inet6AddressToAscii(address);
throw new AssertionError("Invalid IPv6 address: '" + host + "'");

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