org.bukkit.block.Block.getLightFromBlocks()方法的使用及代码示例

x33g5p2x  于2022-01-16 转载在 其他  
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本文整理了Java中org.bukkit.block.Block.getLightFromBlocks()方法的一些代码示例,展示了Block.getLightFromBlocks()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。Block.getLightFromBlocks()方法的具体详情如下:
包路径:org.bukkit.block.Block
类名称:Block
方法名:getLightFromBlocks

Block.getLightFromBlocks介绍

[英]Get the amount of light at this block from nearby blocks.

Any light given from other sources (such as the sun) will be ignored.
[中]从附近街区获取该街区的光量。
从其他光源(如太阳)发出的任何光线都将被忽略。

代码示例

代码示例来源:origin: bergerkiller/BKCommonLib

@Override
public byte getLightFromBlocks() {
  return base.getLightFromBlocks();
}

代码示例来源:origin: AddstarMC/Minigames

@Override
public ScriptReference get(String name) {
  if (name.equalsIgnoreCase("pos")) {
    return wrap(object.getLocation());
  } else if (name.equalsIgnoreCase("type")) {
    return ScriptValue.of(object.getType());
  } else if (name.equalsIgnoreCase("data")) {
    return ScriptValue.of(object.getBlockData());
  } else if (name.equalsIgnoreCase("temperature")) {
    return ScriptValue.of(object.getTemperature());
  } else if (name.equalsIgnoreCase("light")) {
    return ScriptValue.of(object.getLightLevel());
  } else if (name.equalsIgnoreCase("blocklight")) {
    return ScriptValue.of(object.getLightFromBlocks());
  } else if (name.equalsIgnoreCase("skylight")) {
    return ScriptValue.of(object.getLightFromSky());
  } else if (name.equalsIgnoreCase("redstone")) {
    return ScriptValue.of(object.getBlockPower());
  }
  
  return null;
}

代码示例来源:origin: BigScary/GriefPrevention

byte lightLevel = adjacentBlock.getLightFromBlocks();
if(lightLevel == 15 && adjacentBlock.getType() == Material.FIRE)

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