com.microsoft.azure.management.Azure.deployments()方法的使用及代码示例

x33g5p2x  于2022-01-17 转载在 其他  
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本文整理了Java中com.microsoft.azure.management.Azure.deployments()方法的一些代码示例,展示了Azure.deployments()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。Azure.deployments()方法的具体详情如下:
包路径:com.microsoft.azure.management.Azure
类名称:Azure
方法名:deployments

Azure.deployments介绍

暂无

代码示例

代码示例来源:origin: jenkinsci/azure-vm-agents-plugin

deployment = azureClient.deployments().
      getByResourceGroup(info.getResourceGroupName(), info.getDeploymentName());
} catch (NullPointerException e) {
      failTimeoutInMinutes);
  azureClient.deployments()
      .deleteByResourceGroup(info.getResourceGroupName(), info.getDeploymentName());
  if (StringUtils.isNotBlank(info.scriptUri)) {
      successTimeoutInMinutes);
  azureClient.deployments()
      .deleteByResourceGroup(info.getResourceGroupName(), info.getDeploymentName());
  if (StringUtils.isNotBlank(info.scriptUri)) {

代码示例来源:origin: jenkinsci/azure-vm-agents-plugin

final Deployment dep = newAzureClient.deployments().getByName(deploymentName);

代码示例来源:origin: jenkinsci/azure-vm-agents-plugin

template.getAzureCloud().getCloudName(), template.getResourceGroupName(), deploymentName, scriptUri);
azureClient.deployments().define(deploymentName)
    .withExistingResourceGroup(template.getResourceGroupName())
    .withTemplate(tmp.toString())

代码示例来源:origin: gradle.plugin.com.intershop.gradle.plugin.azure/azurePlugin

deployment = getClient().deployments()
        .define(deploymentId.get())
        .withExistingResourceGroup(resourceGroup.get().name())
deployment = getClient().deployments()
        .define(deploymentId.get())
        .withExistingResourceGroup(resourceGroup.get().name())

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