本文整理了Java中org.apache.usergrid.persistence.Query.fromQueryParams方法的一些代码示例，展示了Query.fromQueryParams的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台，是从一些精选项目中提取出来的代码，具有较强的参考意义，能在一定程度帮忙到你。Query.fromQueryParams方法的具体详情如下：
包路径：org.apache.usergrid.persistence.Query
类名称：Query
方法名：fromQueryParams

Query.fromQueryParams介绍

暂无

代码示例

代码示例来源：origin: apache/usergrid

public static Query fromJsonString( String json ) throws QueryParseException {
  Object o;
  try {
    o = mapper.readValue( json, Object.class );
  } catch (IOException ex) {
    throw new QueryParseException("Error parsing JSON query string " + json, ex);
  }
  if ( o instanceof Map ) {
    @SuppressWarnings({ "unchecked", "rawtypes" }) Map<String, List<String>> params =
        ClassUtils.cast( MapUtils.toMapList( ( Map ) o ) );
    return fromQueryParams( params );
  }
  return null;
}

代码示例来源：origin: apache/usergrid

@Test
public void testQueryParamsWithUrlEncodedPlus(){
  String qlString = "select * where email='test+value@usergrid.com'";
  Map<String,List<String>> queryParams = new HashMap<>();
  queryParams.put("ql", Collections.singletonList(qlString.replace("+", "%2b")));
  Query query = Query.fromQueryParams(queryParams);
  assertEquals(qlString, query.getQl().get());
}

代码示例来源：origin: apache/usergrid

@Test
public void testQueryParamsWithPlus(){
  String qlString = "select * where email='test+value@usergrid.com'";
  Map<String,List<String>> queryParams = new HashMap<>();
  queryParams.put("ql", Collections.singletonList(qlString) );
  Query query = Query.fromQueryParams(queryParams);
  assertEquals(qlString, query.getQl().get());
}