io.vertx.core.buffer.Buffer.setIntLE()方法的使用及代码示例

x33g5p2x  于2022-01-16 转载在 其他  
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本文整理了Java中io.vertx.core.buffer.Buffer.setIntLE()方法的一些代码示例,展示了Buffer.setIntLE()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。Buffer.setIntLE()方法的具体详情如下:
包路径:io.vertx.core.buffer.Buffer
类名称:Buffer
方法名:setIntLE

Buffer.setIntLE介绍

[英]Sets the int at position pos in the Buffer to the value i in the Little Endian Byte Order.

The buffer will expand as necessary to accommodate any value written.
[中]将缓冲区中位置pos处的int设置为小尾端字节顺序的值i。
缓冲区将根据需要扩展以容纳任何写入的值。

代码示例

代码示例来源:origin: eclipse-vertx/vert.x

private void testGetSetInt(boolean isLE) throws Exception {
 int numInts = 100;
 Buffer b = Buffer.buffer(numInts * 4);
 for (int i = 0; i < numInts; i++) {
  if (isLE) {
   b.setIntLE(i * 4, i);
  } else {
   b.setInt(i * 4, i);
  }
 }
 for (int i = 0; i < numInts; i++) {
  if (isLE) {
   assertEquals(i, b.getIntLE(i * 4));
  } else {
   assertEquals(i, b.getInt(i * 4));
  }
 }
}

代码示例来源:origin: io.vertx/vertx-rx-java

/**
 * Sets the <code>int</code> at position <code>pos</code> in the Buffer to the value <code>i</code> in the Little Endian Byte Order.<p>
 * The buffer will expand as necessary to accommodate any value written.
 * @param pos 
 * @param i 
 * @return 
 */
public io.vertx.rxjava.core.buffer.Buffer setIntLE(int pos, int i) { 
 delegate.setIntLE(pos, i);
 return this;
}

代码示例来源:origin: vert-x3/vertx-rx

/**
 * Sets the <code>int</code> at position <code>pos</code> in the Buffer to the value <code>i</code> in the Little Endian Byte Order.<p>
 * The buffer will expand as necessary to accommodate any value written.
 * @param pos 
 * @param i 
 * @return 
 */
public io.vertx.rxjava.core.buffer.Buffer setIntLE(int pos, int i) { 
 delegate.setIntLE(pos, i);
 return this;
}

代码示例来源:origin: io.vertx/vertx-core

private void testGetSetInt(boolean isLE) throws Exception {
 int numInts = 100;
 Buffer b = Buffer.buffer(numInts * 4);
 for (int i = 0; i < numInts; i++) {
  if (isLE) {
   b.setIntLE(i * 4, i);
  } else {
   b.setInt(i * 4, i);
  }
 }
 for (int i = 0; i < numInts; i++) {
  if (isLE) {
   assertEquals(i, b.getIntLE(i * 4));
  } else {
   assertEquals(i, b.getInt(i * 4));
  }
 }
}

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