com.google.android.exoplayer2.util.Util.isLinebreak()方法的使用及代码示例

x33g5p2x  于2022-02-01 转载在 其他  
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本文整理了Java中com.google.android.exoplayer2.util.Util.isLinebreak()方法的一些代码示例,展示了Util.isLinebreak()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。Util.isLinebreak()方法的具体详情如下:
包路径:com.google.android.exoplayer2.util.Util
类名称:Util
方法名:isLinebreak

Util.isLinebreak介绍

[英]Returns whether the given character is a carriage return ('\r') or a line feed ('\n').
[中]返回给定字符是回车符('\r')还是换行符('\n')。

代码示例

代码示例来源:origin: google/ExoPlayer

private static int skipIgnorableWhitespace(BufferedReader reader, boolean skipLinebreaks, int c)
  throws IOException {
 while (c != -1 && Character.isWhitespace(c) && (skipLinebreaks || !Util.isLinebreak(c))) {
  c = reader.read();
 }
 return c;
}

代码示例来源:origin: google/ExoPlayer

private static boolean checkPlaylistHeader(BufferedReader reader) throws IOException {
 int last = reader.read();
 if (last == 0xEF) {
  if (reader.read() != 0xBB || reader.read() != 0xBF) {
   return false;
  }
  // The playlist contains a Byte Order Mark, which gets discarded.
  last = reader.read();
 }
 last = skipIgnorableWhitespace(reader, true, last);
 int playlistHeaderLength = PLAYLIST_HEADER.length();
 for (int i = 0; i < playlistHeaderLength; i++) {
  if (last != PLAYLIST_HEADER.charAt(i)) {
   return false;
  }
  last = reader.read();
 }
 last = skipIgnorableWhitespace(reader, false, last);
 return Util.isLinebreak(last);
}

代码示例来源:origin: google/ExoPlayer

while (lineLimit < limit && !Util.isLinebreak(data[lineLimit])) {
 lineLimit++;

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